-52x^2+206=206

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Solution for -52x^2+206=206 equation: 



-52x^2+206=206

We move all terms to the left:

-52x^2+206-(206)=0

We add all the numbers together, and all the variables

-52x^2=0

a = -52; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-52)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-104}=0$

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